1. Вычисления:
- а) \( 7 + 4\frac{17}{19} = 7 + 4 + \frac{17}{19} = 11\frac{17}{19} \)
- б) \( 5\frac{3}{7} + 2\frac{2}{7} = (5+2) + (\frac{3}{7} + \frac{2}{7}) = 7 + \frac{5}{7} = 7\frac{5}{7} \)
- в) \( 8\frac{5}{13} + 3\frac{10}{13} = (8+3) + (\frac{5}{13} + \frac{10}{13}) = 11 + \frac{15}{13} = 11 + 1\frac{2}{13} = 12\frac{2}{13} \)
- г) \( 7 - 4\frac{17}{19} = 6\frac{19}{19} - 4\frac{17}{19} = (6-4) + (\frac{19}{19} - \frac{17}{19}) = 2 + \frac{2}{19} = 2\frac{2}{19} \)
- д) \( 5\frac{3}{7} - 2\frac{2}{7} = (5-2) + (\frac{3}{7} - \frac{2}{7}) = 3 + \frac{1}{7} = 3\frac{1}{7} \)
- е) \( 8\frac{5}{13} - 3\frac{10}{13} = 7\frac{18}{13} - 3\frac{10}{13} = (7-3) + (\frac{18}{13} - \frac{10}{13}) = 4 + \frac{8}{13} = 4\frac{8}{13} \)
Ответ: а) \( 11\frac{17}{19} \); б) \( 7\frac{5}{7} \); в) \( 12\frac{2}{13} \); г) \( 2\frac{2}{19} \); д) \( 3\frac{1}{7} \); е) \( 4\frac{8}{13} \).