Ответ:
Решение:
- а) \(\frac{1}{5} + \frac{53}{50} = \frac{1 × 10}{5 × 10} + \frac{53}{50} = \frac{10}{50} + \frac{53}{50} = \frac{10+53}{50} = \frac{63}{50}\)
- б) \(\frac{1}{5} + \frac{19}{20} = \frac{1 × 4}{5 × 4} + \frac{19}{20} = \frac{4}{20} + \frac{19}{20} = \frac{4+19}{20} = \frac{23}{20}\)
- в) \(\frac{1}{2} + \frac{33}{50} = \frac{1 × 25}{2 × 25} + \frac{33}{50} = \frac{25}{50} + \frac{33}{50} = \frac{25+33}{50} = \frac{58}{50} = \frac{29}{25}\)
- г) \(\frac{1}{5} - \frac{41}{50} = \frac{1 × 10}{5 × 10} - \frac{41}{50} = \frac{10}{50} - \frac{41}{50} = \frac{10-41}{50} = -\frac{31}{50}\)
Ответ: а) \(\frac{63}{50}\), б) \(\frac{23}{20}\), в) \(\frac{29}{25}\), г) -\(\frac{31}{50}\).
