Ответ:
Используем формулы приведения и значения тригонометрических функций для углов 30°, 45° и 60°.
- 150° = 180° − 30°:
\(\sin 150° = \sin 30° = \frac{1}{2}\);
\(\cos 150° = -\cos 30° = -\frac{\sqrt{3}}{2}\);
\( g 150° = - g 30° = -\frac{\sqrt{3}}{3}\);
\(\ctg 150° = -\ctg 30° = -\sqrt{3}\). - 225° = 180° + 45°:
\(\sin 225° = -\sin 45° = -\frac{\sqrt{2}}{2}\);
\(\cos 225° = -\cos 45° = -\frac{\sqrt{2}}{2}\);
\( g 225° = g 45° = 1\);
\(\ctg 225° = \ctg 45° = 1\). - 240° = 180° + 60°:
\(\sin 240° = -\sin 60° = -\frac{\sqrt{3}}{2}\);
\(\cos 240° = -\cos 60° = -\frac{1}{2}\);
\( g 240° = g 60° = \sqrt{3}\);
\(\ctg 240° = \ctg 60° = \frac{\sqrt{3}}{3}\). - 315° = 360° − 45°:
\(\sin 315° = -\sin 45° = -\frac{\sqrt{2}}{2}\);
\(\cos 315° = \cos 45° = \frac{\sqrt{2}}{2}\);
\( g 315° = - g 45° = -1\);
\(\ctg 315° = -\ctg 45° = -1\).
Ответ: а) \(\sin150°=\frac12\), \(\cos150°=-\frac{\sqrt3}{2}\), \( g150°=-\frac{\sqrt3}{3}\), \(\ctg150°=-\sqrt3\); б) \(\sin225°=\cos225°=-\frac{\sqrt2}{2}\), \( g225°=\ctg225°=1\); в) \(\sin240°=-\frac{\sqrt3}{2}\), \(\cos240°=-\frac12\), \( g240°=\sqrt3\), \(\ctg240°=\frac{\sqrt3}{3}\); г) \(\sin315°=-\frac{\sqrt2}{2}\), \(\cos315°=\frac{\sqrt2}{2}\), \( g315°=\ctg315°=-1\).
