Ответ:
а) \(5.1 \cdot \frac{2}{3}-2\frac{1}{4}=\frac{51}{10}\cdot\frac{2}{3}-\frac{9}{4}=\frac{17}{5}-\frac{9}{4}=\frac{68-45}{20}=\frac{23}{20}=1.15\).
б) \(\frac{5\frac{1}{6}\cdot7.5\cdot2.3}{4.6\cdot2\frac{7}{12}\cdot4.5}=\frac{\frac{31}{6}\cdot7.5\cdot2.3}{4.6\cdot\frac{31}{12}\cdot4.5}=\frac{5}{3}\).
в) \(1\frac{7}{9}+\left(6\frac{3}{4}:3.125-2.5:3\frac{1}{8}\right)\cdot7.5-2\frac{8}{15}\).
\(6\frac{3}{4}:3.125=\frac{27}{4}:\frac{25}{8}=\frac{54}{25}\), а \(2.5:3\frac{1}{8}=\frac{5}{2}:\frac{25}{8}=\frac{4}{5}\).
Тогда \(\frac{54}{25}-\frac{4}{5}=\frac{34}{25}\), и \(\frac{34}{25}\cdot7.5=\frac{34}{25}\cdot\frac{15}{2}=\frac{51}{5}\).
\(\frac{16}{9}+\frac{51}{5}-\frac{38}{15}=\frac{80+459-114}{45}=\frac{425}{45}=\frac{85}{9}=9\frac{4}{9}\).
Ответ: а) \(1.15\); б) \(\frac{5}{3}\); в) \(9\frac{4}{9}\).
