Ответ:
- \(\frac{7}{27}+\frac{16}{27}-\frac{19}{27}=\frac{7+16-19}{27}=\frac{4}{27}\).
- \(4\frac{12}{19}-2\frac{2}{19}+7\frac{9}{19}=9+\frac{12-2+9}{19}=9\frac{19}{19}=10\).
- \(1-\frac{18}{27}=\frac{27}{27}-\frac{18}{27}=\frac{9}{27}=\frac{1}{3}\).
- \(6\frac{2}{9}-4\frac{5}{9}=2-\frac{3}{9}=2-\frac{1}{3}=1\frac{2}{3}\).
Ответ: а) \(\frac{4}{27}\); б) \(10\); в) \(\frac{1}{3}\); г) \(1\frac{2}{3}\).
