Ответ:
а) \(\frac{4}{9}\cdot\frac{27}{40}=\frac{4\cdot27}{9\cdot40}=\frac{3}{10}\).
б) \(7\cdot\frac{15}{28}=\frac{7\cdot15}{28}=\frac{15}{4}=3\frac{3}{4}\).
в) \(5\frac{3}{5}=\frac{28}{5}\), поэтому \(\frac{28}{5}\cdot\frac{3}{7}=\frac{12}{5}=2\frac{2}{5}\).
г) \(2\frac{6}{11}=\frac{28}{11}\), \(2\frac{5}{14}=\frac{33}{14}\). Тогда \(\frac{28}{11}\cdot\frac{33}{14}=6\).
д) \(1\frac{7}{8}=\frac{15}{8}\), \(1\frac{1}{15}=\frac{16}{15}\), \(1\frac{1}{16}=\frac{17}{16}\). Тогда \(\frac{15}{8}\cdot\frac{16}{15}\cdot\frac{17}{16}=\frac{17}{8}=2\frac{1}{8}\).
Ответ: а) \(\frac{3}{10}\); б) \(3\frac{3}{4}\); в) \(2\frac{2}{5}\); г) \(6\); д) \(2\frac{1}{8}\).
