1) (x²-2)²-9(x²-2)+14=0;

Let y = x²-2. The equation becomes y² - 9y + 14 = 0. Factoring gives (y-2)(y-7) = 0. So, y=2 or y=7. Substituting back, x²-2=2 gives x²=4, so x=±2. And x²-2=7 gives x²=9, so x=±3. The solutions are x = ±2, ±3.