Решение:
- \( x^2 = 64 \)
\( x = \pm\sqrt{64} \)
\( x = \pm 8 \) - \( x^2 + 8x = 0 \)
\( x(x + 8) = 0 \)
\( x = 0 \) или \( x = -8 \) - \( x^2 + 8x + 16 = 0 \)
\( (x + 4)^2 = 0 \)
\( x = -4 \) - \( x^2 = 225 \)
\( x = \pm\sqrt{225} \)
\( x = \pm 15 \) - \( x^2 = 8x \)
\( x^2 - 8x = 0 \)
\( x(x - 8) = 0 \)
\( x = 0 \) или \( x = 8 \) - \( x^2 = 5x - 6 \)
\( x^2 - 5x + 6 = 0 \)
\( (x - 2)(x - 3) = 0 \)
\( x = 2 \) или \( x = 3 \) - \( x^2 - 4 = 0 \)
\( x^2 = 4 \)
\( x = \pm\sqrt{4} \)
\( x = \pm 2 \) - \( (x - 1)(-x - 4) = 0 \)
\( x - 1 = 0 \) или \( -x - 4 = 0 \)
\( x = 1 \) или \( x = -4 \) - \( 4x^2 - 20x = 0 \)
\( 4x(x - 5) = 0 \)
\( x = 0 \) или \( x = 5 \) - \( 2x^2 - 9x - 5 = 0 \)
\( D = (-9)^2 - 4 x 2 x (-5) = 81 + 40 = 121 \)
\( x = \frac{9 \pm\sqrt{121}}{2 x 2} = \frac{9 \pm 11}{4} \)
\( x_1 = \frac{9 + 11}{4} = \frac{20}{4} = 5 \), \( x_2 = \frac{9 - 11}{4} = \frac{-2}{4} = -0.5 \) - \( x^2 + 16 = 0 \)
\( x^2 = -16 \)
Нет действительных решений. - \( x^2 - 4x + 16 = 0 \)
\( D = (-4)^2 - 4 x 1 x 16 = 16 - 64 = -48 \)
Нет действительных решений.
Ответ: 1. \( x = \pm 8 \); 2. \( x = 0, x = -8 \); 3. \( x = -4 \); 4. \( x = \pm 15 \); 5. \( x = 0, x = 8 \); 6. \( x = 2, x = 3 \); 7. \( x = \pm 2 \); 8. \( x = 1, x = -4 \); 9. \( x = 0, x = 5 \); 10. \( x = 5, x = -0.5 \); 11. Нет действительных решений; 12. Нет действительных решений.