10. Вычислите: (3 - 2/15 - 2/18) + 12 * (1 + 5/6 + 5/4) Б) 44 * (5/33 - 4/22) - 5 * (8/15 - 7/10 - 9/30) Ж) 9 * (5/18 + 11/27) - 11 * (4/11 - 3/33) Д) 16 * (5/21 - 3/84 + 79/84) + 15 * (1/2 + 1/3 + 4/5) Е) 7 * (6/21 + 4/14) - 11 * (3/22 - 37/44) 17. (5 + 9/51 + 7/34) - 7 * (57 - 5/21 - 9/84 - 11/12)

Решение:

10.

1. \( \left( 3 - \frac{2}{15} - \frac{2}{18} \right) = \left( 3 - \frac{2}{15} - \frac{1}{9} \right) = \left( \frac{135 - 6 - 5}{45} \right) = \frac{124}{45} \)
2. \( \left( 1 + \frac{5}{6} + \frac{5}{4} \right) = \left( \frac{12 + 10 + 15}{12} \right) = \frac{37}{12} \)
3. \( \frac{124}{45} + 12 \cdot \frac{37}{12} = \frac{124}{45} + 37 = \frac{124 + 1665}{45} = \frac{1789}{45} \)

Б)

1. \( \frac{4}{22} = \frac{2}{11} \)
2. \( \frac{8}{33} - \frac{2}{11} = \frac{8 - 6}{33} = \frac{2}{33} \)
3. \( \frac{7}{10} + \frac{9}{30} = \frac{21 + 9}{30} = \frac{30}{30} = 1 \)
4. \( \frac{8}{15} - 1 = \frac{8 - 15}{15} = -\frac{7}{15} \)
5. \( 44 \cdot \frac{2}{33} - 5 \cdot \left(-\frac{7}{15}\right) = \frac{8}{3} + \frac{35}{15} = \frac{40 + 35}{15} = \frac{75}{15} = 5 \)

Ж)

1. \( \frac{5}{18} + \frac{11}{27} = \frac{15 + 22}{54} = \frac{37}{54} \)
2. \( \frac{4}{11} - \frac{3}{33} = \frac{12 - 3}{33} = \frac{9}{33} = \frac{3}{11} \)
3. \( 9 \cdot \frac{37}{54} - 11 \cdot \frac{3}{11} = \frac{37}{6} - 3 = \frac{37 - 18}{6} = \frac{19}{6} \)

Д)

1. \( \frac{3}{84} = \frac{1}{28} \)
2. \( \frac{5}{21} - \frac{1}{28} + \frac{79}{84} = \frac{20 - 7 + 79}{84} = \frac{92}{84} = \frac{23}{21} \)
3. \( \frac{1}{2} + \frac{1}{3} + \frac{4}{5} = \frac{15 + 10 + 24}{30} = \frac{49}{30} \)
4. \( 16 \cdot \frac{23}{21} + 15 \cdot \frac{49}{30} = \frac{368}{21} + \frac{49}{2} = \frac{736 + 1029}{42} = \frac{1765}{42} \)

Е)

1. \( \frac{6}{21} = \frac{2}{7} \)
2. \( \frac{2}{7} + \frac{4}{14} = \frac{2}{7} + \frac{2}{7} = \frac{4}{7} \)
3. \( \frac{3}{22} - \frac{37}{44} = \frac{6 - 37}{44} = -\frac{31}{44} \)
4. \( 7 \cdot \frac{4}{7} - 11 \cdot \left(-\frac{31}{44}\right) = 4 + \frac{31}{4} = \frac{16 + 31}{4} = \frac{47}{4} \)

17.

1. \( 5 + \frac{9}{51} + \frac{7}{34} = 5 + \frac{3}{17} + \frac{7}{34} = \frac{170 + 6 + 7}{34} = \frac{183}{34} \)
2. \( 57 - \frac{5}{21} - \frac{9}{84} - \frac{11}{12} = 57 - \frac{5}{21} - \frac{3}{28} - \frac{11}{12} = \frac{2394 - 20 - 21 - 99}{84} = \frac{2254}{84} = \frac{1127}{42} \)
3. \( \frac{183}{34} - 7 \cdot \frac{1127}{42} = \frac{183}{34} - \frac{1127}{6} = \frac{183 - 13036}{204} = -\frac{12853}{204} \)

Ответ: 10. \( \frac{1789}{45} \); Б) 5; Ж) \( \frac{19}{6} \); Д) \( \frac{1765}{42} \); Е) \( \frac{47}{4} \); 17. \( -\frac{12853}{204} \).