Ответ:
120°:
\(120°=180°-60°\).
\(\sin120°=\sin60°=\frac{\sqrt3}{2}\), \(\cos120°=-\cos60°=-\frac12\), \(\tan120°=-\tan60°=-\sqrt3\).
135°:
\(135°=180°-45°\).
\(\sin135°=\sin45°=\frac{\sqrt2}{2}\), \(\cos135°=-\cos45°=-\frac{\sqrt2}{2}\), \(\tan135°=-\tan45°=-1\).
150°:
\(150°=180°-30°\).
\(\sin150°=\sin30°=\frac12\), \(\cos150°=-\cos30°=-\frac{\sqrt3}{2}\), \(\tan150°=-\tan30°=-\frac{\sqrt3}{3}\).
Ответ: \(120°:\ \sin=\frac{\sqrt3}{2},\ \cos=-\frac12,\ \tan=-\sqrt3;\quad 135°:\ \sin=\frac{\sqrt2}{2},\ \cos=-\frac{\sqrt2}{2},\ \tan=-1;\quad 150°:\ \sin=\frac12,\ \cos=-\frac{\sqrt3}{2},\ \tan=-\frac{\sqrt3}{3}\).
