11 (22)5.2 (23)3 =

11. $$\frac{(2^2)^5 \cdot 2}{(2^3)^3} = \frac{2^{2\cdot5} \cdot 2}{2^{3\cdot3}} = \frac{2^{10} \cdot 2}{2^9} = \frac{2^{10+1}}{2^9} = \frac{2^{11}}{2^9} = 2^{11-9} = 2^2 = 4$$

Ответ: 4