11) (2a+3b−5)/a² + 5b/a² =

\(\frac{2a+3b-5}{a^2}+\frac{5b}{a^2}=\frac{2a+3b-5+5b}{a^2}=\frac{2a+8b-5}{a^2}\).

Ответ: \(\frac{2a+8b-5}{a^2}\)