Вопрос:

11. Решите уравнение: 1) 3(x - 2) = x + 2; 2) 5 - 2(x - 1) = 4 - x; 3) (7x + 1) - (9x + 3) = 5; 4) 3,4 + 2y = 7(y - 2,3); 5) 0,2(7 - 2y) = 2,3 - 0,3(y - 6); 6) 2 1/3 (1/3 x - 1/2) = 4x + 2 1/2

Ответ:

Решение:

  1. \( 3(x - 2) = x + 2 \)
    \( 3x - 6 = x + 2 \)
    \( 3x - x = 2 + 6 \)
    \( 2x = 8 \)
    \( x = \frac{8}{2} \)
    \( x = 4 \)
  2. \( 5 - 2(x - 1) = 4 - x \)
    \( 5 - 2x + 2 = 4 - x \)
    \( 7 - 2x = 4 - x \)
    \( 7 - 4 = 2x - x \)
    \( 3 = x \)
  3. \( (7x + 1) - (9x + 3) = 5 \)
    \( 7x + 1 - 9x - 3 = 5 \)
    \( -2x - 2 = 5 \)
    \( -2x = 5 + 2 \)
    \( -2x = 7 \)
    \( x = -\frac{7}{2} \)
    \( x = -3,5 \)
  4. \( 3,4 + 2y = 7(y - 2,3) \)
    \( 3,4 + 2y = 7y - 16,1 \)
    \( 3,4 + 16,1 = 7y - 2y \)
    \( 19,5 = 5y \)
    \( y = \frac{19,5}{5} \)
    \( y = 3,9 \)
  5. \( 0,2(7 - 2y) = 2,3 - 0,3(y - 6) \)
    \( 1,4 - 0,4y = 2,3 - 0,3y + 1,8 \)
    \( 1,4 - 0,4y = 4,1 - 0,3y \)
    \( 1,4 - 4,1 = 0,4y - 0,3y \)
    \( -2,7 = 0,1y \)
    \( y = \frac{-2,7}{0,1} \)
    \( y = -27 \)
  6. \( 2\frac{1}{3} \left( \frac{1}{3} x - \frac{1}{2} \right) = 4x + 2\frac{1}{2} \)
    \( \frac{7}{3} \left( \frac{1}{3} x - \frac{1}{2} \right) = 4x + \frac{5}{2} \)
    \( \frac{7}{9} x - \frac{7}{6} = 4x + \frac{5}{2} \)
    \( \frac{7}{9} x - 4x = \frac{5}{2} + \frac{7}{6} \)
    \( \frac{7 - 36}{9} x = \frac{15 + 7}{6} \)
    \( -\frac{29}{9} x = \frac{22}{6} \)
    \( -\frac{29}{9} x = \frac{11}{3} \)
    \( x = \frac{11}{3} \cdot \left(-\frac{9}{29}\right) \)
    \( x = \frac{11}{1} \cdot \left(-\frac{3}{29}\right) \)
    \( x = -\frac{33}{29} \)

Ответ: 1) x = 4; 2) x = 3; 3) x = -3,5; 4) y = 3,9; 5) y = -27; 6) x = -33/29.