118. Возведите в степень: а) \(\left(\frac{2a}{p^2q^3}\right)^4\); б) \(\left(\frac{3a^2b^3}{s^4}\right)^2\); в) \(\left(-\frac{2a^2b}{3mn^3}\right)^2\); г) \(\left(-\frac{3x^2}{2y^3}\right)^3\).

Используем правило: \(\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}\) и \((a^m)^n=a^{mn}\).

1. \[\left(\frac{2a}{p^2q^3}\right)^4=\frac{2^4a^4}{p^8q^{12}}=\frac{16a^4}{p^8q^{12}}.\]
2. \[\left(\frac{3a^2b^3}{s^4}\right)^2=\frac{3^2a^4b^6}{s^8}=\frac{9a^4b^6}{s^8}.\]
3. \[\left(-\frac{2a^2b}{3mn^3}\right)^2=\frac{2^2a^4b^2}{3^2m^2n^6}=\frac{4a^4b^2}{9m^2n^6}.\]
4. \[\left(-\frac{3x^2}{2y^3}\right)^3=-\frac{3^3x^6}{2^3y^9}=-\frac{27x^6}{8y^9}.\]

Ответ: а) \(\frac{16a^4}{p^8q^{12}}\); б) \(\frac{9a^4b^6}{s^8}\); в) \(\frac{4a^4b^2}{9m^2n^6}\); г) \(-\frac{27x^6}{8y^9}\).