Ответ:
\(2\left\lvert2\cdot\frac32-\frac38\right\rvert+\frac34=2\left\lvert3-\frac38\right\rvert+\frac34=2\cdot\frac{21}{8}+\frac34=\frac{21}{4}+\frac34=6\).
Ответ: \(6\).
\(2\left\lvert2\cdot\frac32-\frac38\right\rvert+\frac34=2\left\lvert3-\frac38\right\rvert+\frac34=2\cdot\frac{21}{8}+\frac34=\frac{21}{4}+\frac34=6\).
Ответ: \(6\).