Решение:
\[ \frac{1}{2} : \frac{2}{3} = \frac{1}{2} \times \frac{3}{2} = \frac{1 \times 3}{2 \times 2} = \frac{3}{4} \]
\[ \frac{1}{6} + \frac{3}{4} \]
\[ \frac{1 \times 2}{6 \times 2} + \frac{3 \times 3}{4 \times 3} = \frac{2}{12} + \frac{9}{12} = \frac{2 + 9}{12} = \frac{11}{12} \]
Ответ: $$\frac{11}{12}$$