Чтобы представить неправильную дробь в виде смешанного числа, нужно числитель разделить на знаменатель. Частное будет целой частью, остаток — числителем новой дроби, а знаменатель останется прежним.
| \( \frac{7}{3} \) | = | \( 2 \frac{1}{3} \) | \( \frac{12}{5} \) | = | \( 2 \frac{2}{5} \) | \( \frac{40}{5} \) | = | \( 8 \) | \( \frac{13}{4} \) | = | \( 3 \frac{1}{4} \) |
| \( \frac{44}{11} \) | = | \( 4 \) | \( \frac{35}{6} \) | = | \( 5 \frac{5}{6} \) | \( \frac{47}{6} \) | = | \( 7 \frac{5}{6} \) | \( \frac{63}{4} \) | = | \( 15 \frac{3}{4} \) |
| \( \frac{19}{7} \) | = | \( 2 \frac{5}{7} \) | \( \frac{8}{3} \) | = | \( 2 \frac{2}{3} \) | \( \frac{25}{5} \) | = | \( 5 \) | \( \frac{98}{9} \) | = | \( 10 \frac{8}{9} \) |
| \( \frac{68}{9} \) | = | \( 7 \frac{5}{9} \) | \( \frac{51}{5} \) | = | \( 10 \frac{1}{5} \) | \( \frac{60}{12} \) | = | \( 5 \) | \( \frac{10}{3} \) | = | \( 3 \frac{1}{3} \) |
| \( \frac{25}{4} \) | = | \( 6 \frac{1}{4} \) | \( \frac{26}{13} \) | = | \( 2 \) | \( \frac{29}{18} \) | = | \( 1 \frac{11}{18} \) | \( \frac{40}{17} \) | = | \( 2 \frac{6}{17} \) |
| \( \frac{9}{5} \) | = | \( 1 \frac{4}{5} \) | \( \frac{15}{3} \) | = | \( 5 \) | \( \frac{75}{8} \) | = | \( 9 \frac{3}{8} \) | \( \frac{53}{6} \) | = | \( 8 \frac{5}{6} \) |
| \( \frac{90}{9} \) | = | \( 10 \) | \( \frac{17}{5} \) | = | \( 3 \frac{2}{5} \) | \( \frac{55}{4} \) | = | \( 13 \frac{3}{4} \) | \( \frac{49}{9} \) | = | \( 5 \frac{4}{9} \) |
| \( \frac{43}{5} \) | = | \( 8 \frac{3}{5} \) | \( \frac{12}{7} \) | = | \( 1 \frac{5}{7} \) | \( \frac{100}{7} \) | = | \( 14 \frac{2}{7} \) | \( \frac{33}{19} \) | = | \( 1 \frac{14}{19} \) |
| \( \frac{24}{7} \) | = | \( 3 \frac{3}{7} \) | \( \frac{15}{5} \) | = | \( 3 \) | \( \frac{81}{27} \) | = | \( 3 \) | \( \frac{59}{5} \) | = | \( 11 \frac{4}{5} \) |