Ответ:\(−3{,}2a\cdot5=−16a\).\(0{,}25\cdot8x=2x\).\(−1{,}5y\cdot(−4)=6y\).\(0{,}5m\cdot(−6)n=−3mn\).\(−0{,}4\cdot3p\cdot(−2q)=2{,}4pq\).\(2{,}5\cdot(−4)k=−10k\).\(−1{,}2\cdot(−5)x\cdot3y=18xy\).\(0{,}125\cdot(−8)a\cdot4b=−4ab\).