144. a; b; c natural sonlar uchun \(\frac{30}{13}=a+\frac{1}{b+\frac{1}{c}}\) tenglik o‘rinli bo‘lsa, \(100a+10b+c\) ifodaning qiymatini toping.

\(\frac{30}{13}=2+\frac{4}{13}\), demak \(a=2\).

\(\frac{1}{b+\frac{1}{c}}=\frac{4}{13}\), shuning uchun \(b+\frac{1}{c}=\frac{13}{4}=3+\frac{1}{4}\). Demak, \(b=3\), \(c=4\).

Hisoblaymiz: \(100a+10b+c=100\cdot2+10\cdot3+4=234\).

Javob: 234.