145. a; b; c natural sonlar uchun \(\frac{35}{11}=a+\frac{1}{b+\frac{1}{c}}\) tenglik o‘rinli bo‘lsa, \(100a+10b+c\) ifodaning qiymatini toping.

\(\frac{35}{11}=3+\frac{2}{11}\), demak \(a=3\).

\(\frac{1}{b+\frac{1}{c}}=\frac{2}{11}\), shuning uchun \(b+\frac{1}{c}=\frac{11}{2}=5+\frac{1}{2}\). Demak, \(b=5\), \(c=2\).

Hisoblaymiz: \(100a+10b+c=100\cdot3+10\cdot5+2=352\).

Javob: 352.