15) 3x² − 10x + 2 = 0

Question

\[D=(-10)^2-4\cdot3\cdot2=100-24=76=4\cdot19.\]

\[x_{1,2}=\frac{10\pm\sqrt{76}}{6}=\frac{10\pm2\sqrt{19}}{6}=\frac{5\pm\sqrt{19}}{3}.\]

Ответ: \(x_1=\frac{5+\sqrt{19}}{3}\), \(x_2=\frac{5-\sqrt{19}}{3}\).

Accepted Answer

\[D=(-10)^2-4\cdot3\cdot2=100-24=76=4\cdot19.\]

\[x_{1,2}=\frac{10\pm\sqrt{76}}{6}=\frac{10\pm2\sqrt{19}}{6}=\frac{5\pm\sqrt{19}}{3}.\]

Ответ: \(x_1=\frac{5+\sqrt{19}}{3}\), \(x_2=\frac{5-\sqrt{19}}{3}\).