Вопрос:

15. Сократите дробь:

Ответ:

Решение:

Для сокращения дробей нужно найти наибольший общий делитель (НОД) числителя и знаменателя и разделить оба числа на него.

Исходная дробьСокращениеРезультат
\( \frac{6}{12} \)\( \frac{6 \div 6}{12 \div 6} = \frac{1}{2} \)\( \frac{1}{2} \)
\( \frac{35}{42} \)\( \frac{35 \div 7}{42 \div 7} = \frac{5}{6} \)\( \frac{5}{6} \)
\( \frac{6}{60} \)\( \frac{6 \div 6}{60 \div 6} = \frac{1}{10} \)\( \frac{1}{10} \)
\( \frac{22}{55} \)\( \frac{22 \div 11}{55 \div 11} = \frac{2}{5} \)\( \frac{2}{5} \)
\( \frac{8}{10} \)\( \frac{8 \div 2}{10 \div 2} = \frac{4}{5} \)\( \frac{4}{5} \)
\( \frac{150}{400} \)\( \frac{150 \div 50}{400 \div 50} = \frac{3}{8} \)\( \frac{3}{8} \)
\( \frac{12}{16} \)\( \frac{12 \div 4}{16 \div 4} = \frac{3}{4} \)\( \frac{3}{4} \)
\( \frac{12}{144} \)\( \frac{12 \div 12}{144 \div 12} = \frac{1}{12} \)\( \frac{1}{12} \)
\( \frac{58}{377} \)\( \frac{58 \div 58}{377 \div 58} = \frac{1}{6.5} \)\( \frac{58}{377} \)
\( \frac{7}{49} \)\( \frac{7 \div 7}{49 \div 7} = \frac{1}{7} \)\( \frac{1}{7} \)
\( \frac{16}{28} \)\( \frac{16 \div 4}{28 \div 4} = \frac{4}{7} \)\( \frac{4}{7} \)
\( \frac{14}{91} \)\( \frac{14 \div 7}{91 \div 7} = \frac{2}{13} \)\( \frac{2}{13} \)
\( \frac{18}{54} \)\( \frac{18 \div 18}{54 \div 18} = \frac{1}{3} \)\( \frac{1}{3} \)
\( \frac{52}{65} \)\( \frac{52 \div 13}{65 \div 13} = \frac{4}{5} \)\( \frac{4}{5} \)
\( \frac{600}{850} \)\( \frac{600 \div 50}{850 \div 50} = \frac{12}{17} \)\( \frac{12}{17} \)
\( \frac{20}{30} \)\( \frac{20 \div 10}{30 \div 10} = \frac{2}{3} \)\( \frac{2}{3} \)
\( \frac{144}{216} \)\( \frac{144 \div 72}{216 \div 72} = \frac{2}{3} \)\( \frac{2}{3} \)
\( \frac{57}{342} \)\( \frac{57 \div 57}{342 \div 57} = \frac{1}{6} \)\( \frac{1}{6} \)
\( \frac{36}{96} \)\( \frac{36 \div 12}{96 \div 12} = \frac{3}{8} \)\( \frac{3}{8} \)
\( \frac{18}{81} \)\( \frac{18 \div 9}{81 \div 9} = \frac{2}{9} \)\( \frac{2}{9} \)
\( \frac{24}{30} \)\( \frac{24 \div 6}{30 \div 6} = \frac{4}{5} \)\( \frac{4}{5} \)
\( \frac{9}{24} \)\( \frac{9 \div 3}{24 \div 3} = \frac{3}{8} \)\( \frac{3}{8} \)
\( \frac{8}{14} \)\( \frac{8 \div 2}{14 \div 2} = \frac{4}{7} \)\( \frac{4}{7} \)
\( \frac{23}{115} \)\( \frac{23 \div 23}{115 \div 23} = \frac{1}{5} \)\( \frac{1}{5} \)
\( \frac{50}{75} \)\( \frac{50 \div 25}{75 \div 25} = \frac{2}{3} \)\( \frac{2}{3} \)
\( \frac{56}{126} \)\( \frac{56 \div 14}{126 \div 14} = \frac{4}{9} \)\( \frac{4}{9} \)
\( \frac{15}{1656} \)\( \frac{15 \div 3}{1656 \div 3} = \frac{5}{552} \)\( \frac{5}{552} \)
\( \frac{5}{55} \)\( \frac{5 \div 5}{55 \div 5} = \frac{1}{11} \)\( \frac{1}{11} \)
\( \frac{32}{48} \)\( \frac{32 \div 16}{48 \div 16} = \frac{2}{3} \)\( \frac{2}{3} \)
\( \frac{10}{15} \)\( \frac{10 \div 5}{15 \div 5} = \frac{2}{3} \)\( \frac{2}{3} \)
\( \frac{10}{22} \)\( \frac{10 \div 2}{22 \div 2} = \frac{5}{11} \)\( \frac{5}{11} \)
\( \frac{126}{840} \)\( \frac{126 \div 42}{840 \div 42} = \frac{3}{20} \)\( \frac{3}{20} \)
\( \frac{4}{4} \)\( \frac{4 \div 4}{4 \div 4} = \frac{1}{1} \)\( 1 \)
\( \frac{78}{390} \)\( \frac{78 \div 78}{390 \div 78} = \frac{1}{5} \)\( \frac{1}{5} \)
\( \frac{88}{484} \)\( \frac{88 \div 44}{484 \div 44} = \frac{2}{11} \)\( \frac{2}{11} \)

Ответ: результаты сокращения дробей представлены в таблице выше.

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