Для сокращения дробей нужно найти наибольший общий делитель (НОД) числителя и знаменателя и разделить оба числа на него.
| Исходная дробь | Сокращение | Результат |
| \( \frac{6}{12} \) | \( \frac{6 \div 6}{12 \div 6} = \frac{1}{2} \) | \( \frac{1}{2} \) |
| \( \frac{35}{42} \) | \( \frac{35 \div 7}{42 \div 7} = \frac{5}{6} \) | \( \frac{5}{6} \) |
| \( \frac{6}{60} \) | \( \frac{6 \div 6}{60 \div 6} = \frac{1}{10} \) | \( \frac{1}{10} \) |
| \( \frac{22}{55} \) | \( \frac{22 \div 11}{55 \div 11} = \frac{2}{5} \) | \( \frac{2}{5} \) |
| \( \frac{8}{10} \) | \( \frac{8 \div 2}{10 \div 2} = \frac{4}{5} \) | \( \frac{4}{5} \) |
| \( \frac{150}{400} \) | \( \frac{150 \div 50}{400 \div 50} = \frac{3}{8} \) | \( \frac{3}{8} \) |
| \( \frac{12}{16} \) | \( \frac{12 \div 4}{16 \div 4} = \frac{3}{4} \) | \( \frac{3}{4} \) |
| \( \frac{12}{144} \) | \( \frac{12 \div 12}{144 \div 12} = \frac{1}{12} \) | \( \frac{1}{12} \) |
| \( \frac{58}{377} \) | \( \frac{58 \div 58}{377 \div 58} = \frac{1}{6.5} \) | \( \frac{58}{377} \) |
| \( \frac{7}{49} \) | \( \frac{7 \div 7}{49 \div 7} = \frac{1}{7} \) | \( \frac{1}{7} \) |
| \( \frac{16}{28} \) | \( \frac{16 \div 4}{28 \div 4} = \frac{4}{7} \) | \( \frac{4}{7} \) |
| \( \frac{14}{91} \) | \( \frac{14 \div 7}{91 \div 7} = \frac{2}{13} \) | \( \frac{2}{13} \) |
| \( \frac{18}{54} \) | \( \frac{18 \div 18}{54 \div 18} = \frac{1}{3} \) | \( \frac{1}{3} \) |
| \( \frac{52}{65} \) | \( \frac{52 \div 13}{65 \div 13} = \frac{4}{5} \) | \( \frac{4}{5} \) |
| \( \frac{600}{850} \) | \( \frac{600 \div 50}{850 \div 50} = \frac{12}{17} \) | \( \frac{12}{17} \) |
| \( \frac{20}{30} \) | \( \frac{20 \div 10}{30 \div 10} = \frac{2}{3} \) | \( \frac{2}{3} \) |
| \( \frac{144}{216} \) | \( \frac{144 \div 72}{216 \div 72} = \frac{2}{3} \) | \( \frac{2}{3} \) |
| \( \frac{57}{342} \) | \( \frac{57 \div 57}{342 \div 57} = \frac{1}{6} \) | \( \frac{1}{6} \) |
| \( \frac{36}{96} \) | \( \frac{36 \div 12}{96 \div 12} = \frac{3}{8} \) | \( \frac{3}{8} \) |
| \( \frac{18}{81} \) | \( \frac{18 \div 9}{81 \div 9} = \frac{2}{9} \) | \( \frac{2}{9} \) |
| \( \frac{24}{30} \) | \( \frac{24 \div 6}{30 \div 6} = \frac{4}{5} \) | \( \frac{4}{5} \) |
| \( \frac{9}{24} \) | \( \frac{9 \div 3}{24 \div 3} = \frac{3}{8} \) | \( \frac{3}{8} \) |
| \( \frac{8}{14} \) | \( \frac{8 \div 2}{14 \div 2} = \frac{4}{7} \) | \( \frac{4}{7} \) |
| \( \frac{23}{115} \) | \( \frac{23 \div 23}{115 \div 23} = \frac{1}{5} \) | \( \frac{1}{5} \) |
| \( \frac{50}{75} \) | \( \frac{50 \div 25}{75 \div 25} = \frac{2}{3} \) | \( \frac{2}{3} \) |
| \( \frac{56}{126} \) | \( \frac{56 \div 14}{126 \div 14} = \frac{4}{9} \) | \( \frac{4}{9} \) |
| \( \frac{15}{1656} \) | \( \frac{15 \div 3}{1656 \div 3} = \frac{5}{552} \) | \( \frac{5}{552} \) |
| \( \frac{5}{55} \) | \( \frac{5 \div 5}{55 \div 5} = \frac{1}{11} \) | \( \frac{1}{11} \) |
| \( \frac{32}{48} \) | \( \frac{32 \div 16}{48 \div 16} = \frac{2}{3} \) | \( \frac{2}{3} \) |
| \( \frac{10}{15} \) | \( \frac{10 \div 5}{15 \div 5} = \frac{2}{3} \) | \( \frac{2}{3} \) |
| \( \frac{10}{22} \) | \( \frac{10 \div 2}{22 \div 2} = \frac{5}{11} \) | \( \frac{5}{11} \) |
| \( \frac{126}{840} \) | \( \frac{126 \div 42}{840 \div 42} = \frac{3}{20} \) | \( \frac{3}{20} \) |
| \( \frac{4}{4} \) | \( \frac{4 \div 4}{4 \div 4} = \frac{1}{1} \) | \( 1 \) |
| \( \frac{78}{390} \) | \( \frac{78 \div 78}{390 \div 78} = \frac{1}{5} \) | \( \frac{1}{5} \) |
| \( \frac{88}{484} \) | \( \frac{88 \div 44}{484 \div 44} = \frac{2}{11} \) | \( \frac{2}{11} \) |
Ответ: результаты сокращения дробей представлены в таблице выше.