16. sin(π/6) = 1/2; cos(π/6) = √3/2; tg(π/6) = 1/√3; ctg(π/6) = √3

Для угла \(\frac{\pi}{6}\): \( g x=\frac{\sin x}{\cos x}\), а \(\ctg x=\frac{\cos x}{\sin x}\).

\( g\frac{\pi}{6}=\frac{\frac12}{\frac{\sqrt3}{2}}=\frac{1}{\sqrt3}=\frac{\sqrt3}{3}\); \(\ctg\frac{\pi}{6}=\frac{\frac{\sqrt3}{2}}{\frac12}=\sqrt3.\)

Ответ: \(\sin\frac{\pi}{6}=\frac12\), \(\cos\frac{\pi}{6}=\frac{\sqrt3}{2}\), \( g\frac{\pi}{6}=\frac{1}{\sqrt3}\), \(\ctg\frac{\pi}{6}=\sqrt3\).