16. Выражения: ж) \(\frac{5}{6} + \frac{3}{8}\) 3) \(\frac{19}{21} - \frac{11}{15}\) и) \(\frac{21}{22} - \frac{3}{55}\) к) \(\frac{5}{42} + \frac{10}{63}\) л) \(\frac{11}{21} - \frac{2}{35}\) м) \(\frac{5}{24} + \frac{7}{60}\)

Решение:

ж) \( \frac{5}{6} + \frac{3}{8} = \frac{5 \cdot 4}{24} + \frac{3 \cdot 3}{24} = \frac{20+9}{24} = \frac{29}{24} = 1\frac{5}{24} \)

3) \( \frac{19}{21} - \frac{11}{15} = \frac{19 \cdot 5}{105} - \frac{11 \cdot 7}{105} = \frac{95-77}{105} = \frac{18}{105} = \frac{6}{35} \)

и) \( \frac{21}{22} - \frac{3}{55} = \frac{21 \cdot 5}{110} - \frac{3 \cdot 2}{110} = \frac{105-6}{110} = \frac{99}{110} = \frac{9}{10} \)

к) \( \frac{5}{42} + \frac{10}{63} = \frac{5 \cdot 3}{126} + \frac{10 \cdot 2}{126} = \frac{15+20}{126} = \frac{35}{126} = \frac{5}{18} \)

л) \( \frac{11}{21} - \frac{2}{35} = \frac{11 \cdot 5}{105} - \frac{2 \cdot 3}{105} = \frac{55-6}{105} = \frac{49}{105} = \frac{7}{15} \)

м) \( \frac{5}{24} + \frac{7}{60} = \frac{5 \cdot 5}{120} + \frac{7 \cdot 2}{120} = \frac{25+14}{120} = \frac{39}{120} = \frac{13}{40} \)

Ответ: ж) \(1\frac{5}{24}\); 3) \(\frac{6}{35}\); и) \(\frac{9}{10}\); к) \(\frac{5}{18}\); л) \(\frac{7}{15}\); м) \(\frac{13}{40}\).