Ответ:
Решение:
- a) \(\frac{5}{6} + \frac{1}{4} = \frac{10}{12} + \frac{3}{12} = \frac{13}{12} = 1\frac{1}{12}\)
- б) \(\frac{7}{8} - \frac{5}{6} = \frac{21}{24} - \frac{20}{24} = \frac{1}{24}\)
- в) \(\frac{3}{10} - \frac{4}{15} = \frac{9}{30} - \frac{8}{30} = \frac{1}{30}\)
- г) \(5 - 3\frac{2}{7} = 5 - \frac{23}{7} = \frac{35}{7} - \frac{23}{7} = \frac{12}{7} = 1\frac{5}{7}\)
- д) \(\frac{4}{9} \cdot \frac{3}{8} = \frac{1}{3} \cdot \frac{1}{2} = \frac{1}{6}\)
- е) \(\frac{5}{8} : \frac{9}{10} = \frac{5}{8} \cdot \frac{10}{9} = \frac{5}{4} \cdot \frac{5}{9} = \frac{25}{36}\)
- ж) \(2\frac{6}{7} : 1\frac{3}{7} = \frac{20}{7} : \frac{10}{7} = \frac{20}{7} \cdot \frac{7}{10} = 2\)
- з) \(6\frac{3}{5} \cdot 10 = \frac{33}{5} \cdot 10 = 33 \cdot 2 = 66\)
Ответ: а) \(1\frac{1}{12}\); б) \(\frac{1}{24}\); в) \(\frac{1}{30}\); г) \(1\frac{5}{7}\); д) \(\frac{1}{6}\); е) \(\frac{25}{36}\); ж) 2; з) 66.
