Ответ:
- а) \(7\cdot5^{-2}+12\cdot10^{-2}=7\cdot\frac{1}{25}+12\cdot\frac{1}{100}=\frac{7}{25}+\frac{3}{25}=\frac{2}{5}\).
- б) \(5\cdot3^{-3}-6\cdot9^{-3}=5\cdot\frac{1}{27}-6\cdot\frac{1}{729}=\frac{135}{729}-\frac{6}{729}=\frac{129}{729}=\frac{43}{243}\).
- в) \(7\cdot6^{-2}-4\cdot\left(\frac{9}{17}\right)^{-1}=7\cdot\frac{1}{36}-4\cdot\frac{17}{9}=\frac{7}{36}-\frac{272}{36}=-\frac{265}{36}\).
- г) \(\left(\frac{2}{7}\right)^{-2}+\left(\frac{5}{14}\right)^{-1}=\left(\frac{7}{2}\right)^2+\frac{14}{5}=\frac{49}{4}+\frac{14}{5}=\frac{245+56}{20}=\frac{301}{20}\).
Ответ: а) 2/5; б) 43/243; в) −265/36; г) 301/20.
