177. Амалҳоро иҷро намоед: а) \((5\frac{3}{7}-3\frac{2}{5})+(3-1\frac{17}{35})-(4\frac{12}{15}-3\frac{19}{105})\); б) \((7\frac{7}{9}-5\frac{1}{3})-(2-1\frac{5}{6})+(9\frac{19}{36}-3\frac{11}{12})\).

а)

Аввал қавсҳоро ҳисоб мекунем:

\(5\frac{3}{7}-3\frac{2}{5}=\frac{38}{7}-\frac{17}{5}=\frac{190-119}{35}=\frac{71}{35}\).

\(3-1\frac{17}{35}=\frac{105}{35}-\frac{52}{35}=\frac{53}{35}\).

\(4\frac{12}{15}-3\frac{19}{105}=4\frac{4}{5}-3\frac{19}{105}=\frac{504}{105}-\frac{334}{105}=\frac{170}{105}=\frac{34}{21}\).

Акнун натиҷаҳоро ҷамъу тарҳ мекунем:

\(\frac{71}{35}+\frac{53}{35}-\frac{34}{21}=\frac{124}{35}-\frac{34}{21}=\frac{372-170}{105}=\frac{202}{105}=1\frac{97}{105}\).

б)

Аввал қавсҳоро ҳисоб мекунем:

\(7\frac{7}{9}-5\frac{1}{3}=\frac{70}{9}-\frac{16}{3}=\frac{70-48}{9}=\frac{22}{9}\).

\(2-1\frac{5}{6}=\frac{12}{6}-\frac{11}{6}=\frac{1}{6}\).

\(9\frac{19}{36}-3\frac{11}{12}=\frac{343}{36}-\frac{141}{36}=\frac{202}{36}=\frac{101}{18}\).

Акнун натиҷаҳоро ҷамъу тарҳ мекунем:

\(\frac{22}{9}-\frac{1}{6}+\frac{101}{18}=\frac{44-3+101}{18}=\frac{142}{18}=\frac{71}{9}=7\frac{8}{9}\).

Ҷавоб: а) \(1\frac{97}{105}\); б) \(7\frac{8}{9}\).