Вопрос:

19. Найдите значение выражения: а) \(1\frac{3}{5}\cdot\frac{9}{16}:2\frac{1}{4}\); б) \(\frac{3}{2}:(\frac{1}{2}-\frac{4}{11})\); в) \(1\frac{1}{5}:(\frac{2}{3}-1\frac{1}{15})\); г) \(28\cdot(\frac{27}{28}-\frac{3}{7})\).

Ответ:

  1. а) \(1\frac{3}{5}=\frac{8}{5}\), \(2\frac{1}{4}=\frac{9}{4}\).
    \[\frac{8}{5}\cdot\frac{9}{16}:\frac{9}{4}=\frac{8}{5}\cdot\frac{9}{16}\cdot\frac{4}{9}=\frac{2}{5}.\]
  2. б) \[\frac{3}{2}:\left(\frac{1}{2}-\frac{4}{11}\right)=\frac{3}{2}:\frac{3}{22}=\frac{3}{2}\cdot\frac{22}{3}=11.\]
  3. в) \(1\frac{1}{5}=\frac{6}{5}\), \(1\frac{1}{15}=\frac{16}{15}\).
    \[\frac{6}{5}:\left(\frac{2}{3}-\frac{16}{15}\right)=\frac{6}{5}:\left(\frac{10}{15}-\frac{16}{15}\right)=\frac{6}{5}:\left(-\frac{2}{5}\right)=-3.\]
  4. г) \[28\cdot\left(\frac{27}{28}-\frac{3}{7}\right)=28\cdot\left(\frac{27}{28}-\frac{12}{28}\right)=28\cdot\frac{15}{28}=15.\]

Ответ: а) \(\frac{2}{5}\); б) \(11\); в) \(-3\); г) \(15\).