Вопрос:
196. Выполните действия:
Ответ:
Решение:
- \(9 + \frac{3}{17} = \frac{9 \cdot 17 + 3}{17} = \frac{153 + 3}{17} = \frac{156}{17}\)
- \(\frac{9}{72} + 5 = \frac{1}{8} + 5 = \frac{1 + 5 \cdot 8}{8} = \frac{1 + 40}{8} = \frac{41}{8}\)
- \(4\frac{5}{18} + 2\frac{4}{18} = \frac{4 \cdot 18 + 5}{18} + \frac{2 \cdot 18 + 4}{18} = \frac{72 + 5 + 36 + 4}{18} = \frac{77 + 40}{18} = \frac{117}{18} = \frac{13}{2}\)
- \(\frac{7}{15} - \frac{3}{15} = \frac{7 - 3}{15} = \frac{4}{15}\)
- \(9\frac{11}{16} + 4\frac{3}{16} - 2\frac{2}{16} = \frac{9 \cdot 16 + 11 + 4 \cdot 16 + 3 - 2 \cdot 16 - 2}{16} = \frac{144 + 11 + 64 + 3 - 32 - 2}{16} = \frac{155 + 67 - 34}{16} = \frac{222 - 34}{16} = \frac{188}{16} = \frac{47}{4}\)
- \(15\frac{7}{10} + 2\frac{2}{10} - 4\frac{1}{10} = \frac{15 \cdot 10 + 7 + 2 \cdot 10 + 2 - 4 \cdot 10 - 1}{10} = \frac{150 + 7 + 20 + 2 - 40 - 1}{10} = \frac{157 + 22 - 41}{10} = \frac{179 - 41}{10} = \frac{138}{10} = \frac{69}{5}\)
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