Ответ:

1а) Приводим к знаменателю 18:

\(\frac{4}{9}=\frac{4\cdot2}{9\cdot2}=\frac{8}{18}\); \(\frac{5}{6}=\frac{5\cdot3}{6\cdot3}=\frac{15}{18}\); \(\frac{7}{2}=\frac{7\cdot9}{2\cdot9}=\frac{63}{18}\).

1б) Приводим к знаменателю 80:

\(\frac{7}{8}=\frac{7\cdot10}{8\cdot10}=\frac{70}{80}\); \(\frac{5}{16}=\frac{5\cdot5}{16\cdot5}=\frac{25}{80}\); \(\frac{21}{40}=\frac{21\cdot2}{40\cdot2}=\frac{42}{80}\).

2а) НОЗ(3, 4) = 12: \(\frac{1}{3}=\frac{4}{12}\), \(\frac{1}{4}=\frac{3}{12}\).

2б) НОЗ(8, 16) = 16: \(\frac{5}{8}=\frac{10}{16}\), \(\frac{3}{16}=\frac{3}{16}\).

2в) НОЗ(8, 20) = 40: \(\frac{5}{8}=\frac{25}{40}\), \(\frac{3}{20}=\frac{6}{40}\).

2г) НОЗ(9, 24) = 72: \(\frac{2}{9}=\frac{16}{72}\), \(\frac{7}{24}=\frac{21}{72}\).

Ответ: 1а) \(8/18, 15/18, 63/18\); 1б) \(70/80, 25/80, 42/80\); 2а) \(4/12, 3/12\); 2б) \(10/16, 3/16\); 2в) \(25/40, 6/40\); 2г) \(16/72, 21/72\).