2) \((10,2-13,15):(5\frac{1}{24}-\frac{3}{11}\cdot11,6875-1\frac{1}{6}):5\frac{4}{11}\)

1. \(10,2-13,15=-2,95=-\frac{59}{20}\).
2. \(11,6875=\frac{187}{16}\), поэтому \(\frac{3}{11}\cdot11,6875=\frac{3}{11}\cdot\frac{187}{16}=\frac{51}{16}\).
3. Вторая скобка: \(5\frac{1}{24}-\frac{51}{16}-1\frac{1}{6}=\frac{121}{24}-\frac{51}{16}-\frac{7}{6}=\frac{11}{16}\).
4. \(-\frac{59}{20}:\frac{11}{16}:\frac{59}{11}=-\frac{59}{20}\cdot\frac{16}{11}\cdot\frac{11}{59}=-\frac45\).

Ответ: \(-\frac45\)