Ответ:

\[ (2\sqrt{7}-\sqrt{6})(2\sqrt{7}+\sqrt{6})=(2\sqrt{7})^2-(\sqrt{6})^2. \]

\[ (2\sqrt{7})^2=4\cdot7=28,\qquad (\sqrt{6})^2=6. \]

\[ 28-6=22. \]

Ответ: 22.