Ответ:

а)

\[\left(1\frac{1}{2}\right)^3-2\frac{2}{3}\cdot1\frac{1}{4}=\left(\frac{3}{2}\right)^3-\frac{8}{3}\cdot\frac{5}{4}=\frac{27}{8}-\frac{10}{3}.\]

Приведём дроби к общему знаменателю:

\[\frac{27}{8}-\frac{10}{3}=\frac{81}{24}-\frac{80}{24}=\frac{1}{24}.\]

б)

\[(3.5-2.9)\cdot\left(4\frac{1}{22}-3\frac{7}{33}\right)=0.6\cdot\left(\frac{89}{22}-\frac{106}{33}\right).\]

\[0.6=\frac{3}{5},\qquad \frac{89}{22}-\frac{106}{33}=\frac{267}{66}-\frac{212}{66}=\frac{55}{66}=\frac{5}{6}.\]

\[\frac{3}{5}\cdot\frac{5}{6}=\frac{1}{2}.\]

в)

\[\left(5\frac{3}{14}-4\frac{4}{7}\right)\cdot\left(3\frac{11}{15}-1\frac{2}{5}\right)=\left(5\frac{3}{14}-4\frac{8}{14}\right)\cdot\left(3\frac{11}{15}-1\frac{6}{15}\right).\]

\[5\frac{3}{14}-4\frac{8}{14}=\frac{73}{14}-\frac{64}{14}=\frac{9}{14},\]

\[3\frac{11}{15}-1\frac{6}{15}=\frac{56}{15}-\frac{21}{15}=\frac{35}{15}=\frac{7}{3}.\]

\[\frac{9}{14}\cdot\frac{7}{3}=\frac{3}{2}.\]

Ответ: а) \(\frac{1}{24}\); б) \(\frac{1}{2}\); в) \(\frac{3}{2}\).