2.427. Вычислите: а) $2\frac{1}{7}\cdot(2\frac{1}{4}:3\frac{6}{7})$; б) $(1\frac{2}{9}+1\frac{5}{9})\cdot1\frac{4}{5}$; в) $(7\frac{1}{3}-5\frac{1}{6}):3\frac{1}{3}$; г) $(2\frac{2}{15}-1\frac{2}{5})\cdot6\frac{1}{4}$; д) $(2\frac{2}{3}+1\frac{5}{6}):4\frac{1}{2}$; е) $(7\frac{1}{8}-6\frac{3}{5}):4\frac{1}{5}$.

Question

Вопрос: $Фото задания: 2.427. Вычислите: а) $2\frac{1}{7}\cdot(2\frac{1}{4}:3\frac{6}{7})$; б) $(1\frac{2}{9}+1\frac{5}{9})\cdot1\frac{4}{5}$;…$ Фото задания

2.427. Вычислите: а) $2\frac{1}{7}\cdot(2\frac{1}{4}:3\frac{6}{7})$; б) $(1\frac{2}{9}+1\frac{5}{9})\cdot1\frac{4}{5}$; в) $(7\frac{1}{3}-5\frac{1}{6}):3\frac{1}{3}$; г) $(2\frac{2}{15}-1\frac{2}{5})\cdot6\frac{1}{4}$; д) $(2\frac{2}{3}+1\frac{5}{6}):4\frac{1}{2}$; е) $(7\frac{1}{8}-6\frac{3}{5}):4\frac{1}{5}$.

Accepted Answer

а) $2\frac{1}{7}\cdot(2\frac{1}{4}:3\frac{6}{7})=\frac{15}{7}\cdot\left(\frac{9}{4}:\frac{27}{7}\right)=\frac{15}{7}\cdot\frac{7}{12}=\frac{5}{4}=1\frac{1}{4}$.

б) $(1\frac{2}{9}+1\frac{5}{9})\cdot1\frac{4}{5}=\left(\frac{11}{9}+\frac{14}{9}\right)\cdot\frac{9}{5}=\frac{25}{9}\cdot\frac{9}{5}=5$.

в) $(7\frac{1}{3}-5\frac{1}{6}):3\frac{1}{3}=\left(\frac{22}{3}-\frac{31}{6}\right):\frac{10}{3}=\frac{13}{6}\cdot\frac{3}{10}=\frac{13}{20}$.

г) $(2\frac{2}{15}-1\frac{2}{5})\cdot6\frac{1}{4}=\left(\frac{32}{15}-\frac{7}{5}\right)\cdot\frac{25}{4}=\frac{11}{15}\cdot\frac{25}{4}=\frac{55}{12}=4\frac{7}{12}$.

д) $(2\frac{2}{3}+1\frac{5}{6}):4\frac{1}{2}=\left(\frac{8}{3}+\frac{11}{6}\right):\frac{9}{2}=\frac{9}{2}\cdot\frac{2}{9}=1$.

е) $(7\frac{1}{8}-6\frac{3}{5}):4\frac{1}{5}=\left(\frac{57}{8}-\frac{33}{5}\right):\frac{21}{5}=\frac{21}{40}\cdot\frac{5}{21}=\frac{1}{8}$.

Ответ: а) $1\frac{1}{4}$; б) $5$; в) $\frac{13}{20}$; г) $4\frac{7}{12}$; д) $1$; е) $\frac{1}{8}$.