Ответ:
Используем свойства степеней: \(a^m\cdot a^n=a^{m+n}\), \(\frac{a^m}{a^n}=a^{m-n}\).
- \(\frac{3^7}{81}=\frac{3^7}{3^4}=3^{7-4}=3^3=27\).
- \(\frac{2^5}{4}=\frac{32}{4}=8\).
- \(\frac{3^5}{27}=\frac{3^5}{3^3}=3^2=9\).
- \(\frac{4^5}{16}=\frac{4^5}{4^2}=4^3=64\).
- \(\frac{5^5}{25}=\frac{5^5}{5^2}=5^3=125\).
- \(\frac{7^4\cdot9^6}{63^4}=\frac{7^4\cdot(3^2)^6}{(7\cdot3^2)^4}=\frac{7^4\cdot3^{12}}{7^4\cdot3^8}=3^4=81\).
- \(\frac{7^8\cdot10^6}{70^6}=\frac{7^8\cdot10^6}{(7\cdot10)^6}=\frac{7^8\cdot10^6}{7^6\cdot10^6}=7^2=49\).
- \(\frac{2^8}{4^4\cdot7^5}=\frac{2^8}{(2^2)^4\cdot7^5}=\frac{2^8}{2^8\cdot7^5}=\frac{1}{7^5}=\frac{1}{16807}\).
- \(\frac{20^7}{4^4\cdot5^5}=\frac{(4\cdot5)^7}{4^4\cdot5^5}=\frac{4^7\cdot5^7}{4^4\cdot5^5}=4^3\cdot5^2=64\cdot25=1600\).
- При \(a=3\): \(\frac{a^{12}\cdot a^6}{a^{18}}=a^{12+6-18}=a^0=1\).
Ответ: а) 27; б) 8; в) 9; г) 64; д) 125; е) 81; ж) 49; з) \(\frac{1}{16807}\); и) 1600; к) 1.
