2) $\frac{7}{40}:2\frac{11}{12}-0,1\cdot\left(1,45:2\frac{1}{3}-\frac{1}{20}:2\frac{1}{3}\right)$;

Question

Вопрос: $Фото задания: 2) $\frac{7}{40}:2\frac{11}{12}-0,1\cdot\left(1,45:2\frac{1}{3}-\frac{1}{20}:2\frac{1}{3}\right)$;$ Фото задания

Accepted Answer

Преобразуем смешанное число: $2\frac{11}{12}=\frac{35}{12}$, $2\frac{1}{3}=\frac{7}{3}$.

\[\frac{7}{40}:\frac{35}{12}=\frac{3}{50}.\]

\[1,45:\frac{7}{3}=\frac{29}{20}\cdot\frac{3}{7}=\frac{87}{140},\qquad \frac{1}{20}:\frac{7}{3}=\frac{3}{140}.\]

\[0,1\cdot\left(\frac{87}{140}-\frac{3}{140}\right)=\frac{1}{10}\cdot\frac{84}{140}=\frac{3}{50}.\]

\[\frac{3}{50}-\frac{3}{50}=0.\]

Ответ: 0.

2) \(\frac{7}{40}:2\frac{11}{12}-0,1\cdot\left(1,45:2\frac{1}{3}-\frac{1}{20}:2\frac{1}{3}\right)\);