Ответ:\(ax+bx+ay+by=x(a+b)+y(a+b)=(a+b)(x+y)\).\(3x+3y+2ax+2ay=3(x+y)+2a(x+y)=(x+y)(3+2a)\).\(ax-ay+bx-by=a(x-y)+b(x-y)=(a+b)(x-y)\).\(2x^2+6x+x+3=2x(x+3)+1(x+3)=(x+3)(2x+1)\).\(3ab+6a+b+2=3a(b+2)+1(b+2)=(b+2)(3a+1)\).