Вопрос:

2. Напишите в рамочке один из знаков <, =, > так, чтобы была верной каждая запись: <math>\(\frac{1}{5}\) \(\square\) \(\frac{3}{10}\)</math> <math>\(\frac{3}{5}\) \(\square\) \(\frac{21}{40}\)</math> <math>\(\frac{2}{7}\) \(\square\) \(\frac{1}{15}\)</math> <math>\(\frac{7}{15}\) \(\square\) \(\frac{2}{5}\)</math> <math>\(\frac{1}{17}\) \(\square\) \(\frac{3}{51}\)</math> <math>\(\frac{17}{40}\) \(\square\) \(\frac{17}{21}\)</math> <math>\(\frac{1}{2}\) \(\square\) \(\frac{3}{4}\)</math> <math>\(\frac{7}{12}\) \(\square\) \(\frac{39}{48}\)</math> <math>\(\frac{2}{9}\) \(\square\) \(\frac{6}{27}\)</math> <math>\(\frac{5}{13}\) \(\square\) \(\frac{5}{11}\)</math> <math>\(\frac{5}{18}\) \(\square\) \(\frac{7}{15}\)</math>

Ответ:

Заполняем пропуски знаками сравнения:

\(\frac{1}{5}\) \(\square\) \(\frac{3}{10}\)\(\frac{2}{10}\) < \(\frac{3}{10}\), значит, ставим знак <.

\(\frac{3}{5}\) \(\square\) \(\frac{21}{40}\)\(\frac{24}{40}\) > \(\frac{21}{40}\), значит, ставим знак >.

\(\frac{2}{7}\) \(\square\) \(\frac{1}{15}\)\(\frac{30}{105}\) > \(\frac{7}{105}\), значит, ставим знак >.

\(\frac{7}{15}\) \(\square\) \(\frac{2}{5}\)\(\frac{7}{15}\) \(\square\) \(\frac{6}{15}\), значит, ставим знак >.

\(\frac{1}{17}\) \(\square\) \(\frac{3}{51}\)\(\frac{3}{51}\) = \(\frac{3}{51}\), значит, ставим знак =.

\(\frac{17}{40}\) \(\square\) \(\frac{17}{21}\)\(\frac{17}{40}\) < \(\frac{17}{21}\), значит, ставим знак <.

\(\frac{1}{2}\) \(\square\) \(\frac{3}{4}\)\(\frac{2}{4}\) < \(\frac{3}{4}\), значит, ставим знак <.

\(\frac{7}{12}\) \(\square\) \(\frac{39}{48}\)\(\frac{28}{48}\) < \(\frac{39}{48}\), значит, ставим знак <.

\(\frac{2}{9}\) \(\square\) \(\frac{6}{27}\)\(\frac{6}{27}\) = \(\frac{6}{27}\), значит, ставим знак =.

\(\frac{5}{13}\) \(\square\) \(\frac{5}{11}\)\(\frac{5}{13}\) < \(\frac{5}{11}\), значит, ставим знак <.

\(\frac{5}{18}\) \(\square\) \(\frac{7}{15}\)\(\frac{25}{90}\) < \(\frac{42}{90}\), значит, ставим знак <.