2. Найдите значение выражения: \(\frac{4}{7}\cdot(1,4x-3,5)+1,2\cdot(3-2x)\), если \(x=-1\frac{1}{8}\).

Подставим \(x=-1\frac{1}{8}=-\frac{9}{8}\), \(1,4=\frac{7}{5}\), \(3,5=\frac{7}{2}\), \(1,2=\frac{6}{5}\):

\[\frac{4}{7}\left(\frac{7}{5}\cdot\left(-\frac{9}{8}\right)-\frac{7}{2}\right)+\frac{6}{5}\left(3-2\cdot\left(-\frac{9}{8}\right)\right)\]

\[=\frac{4}{7}\left(-\frac{63}{40}-\frac{140}{40}\right)+\frac{6}{5}\left(3+\frac{9}{4}\right)\]

\[=-\frac{203}{70}+\frac{63}{10}=-\frac{203}{70}+\frac{441}{70}=\frac{238}{70}=\frac{17}{5}=3,4.\]

Ответ: \(3,4\).