Решение:
- \( 1 - 10x = -5x + 10 \)
\( -10x + 5x = 10 - 1 \)
\( -5x = 9 \)
\( x = -\frac{9}{5} \) - \( x^2 - 12x + 20 = 0 \)
\( D = (-12)^2 - 4 \cdot 1 \cdot 20 = 144 - 80 = 64 \)
\( \sqrt{D} = 8 \)
\( x_1 = \frac{12 + 8}{2} = 10 \)
\( x_2 = \frac{12 - 8}{2} = 2 \)
Ответ: 1) \( x = -\frac{9}{5} \); 2) \( x_1 = 10, x_2 = 2 \).