Ответ:
\(3\sqrt{12}+2\sqrt{27}-\sqrt{75}=3\cdot2\sqrt{3}+2\cdot3\sqrt{3}-5\sqrt{3}\).
\(=6\sqrt{3}+6\sqrt{3}-5\sqrt{3}=7\sqrt{3}\).
\(5-\sqrt{18}-3\sqrt{8}+2\sqrt{50}=5-3\sqrt{2}-3\cdot2\sqrt{2}+2\cdot5\sqrt{2}\).
\(=5-3\sqrt{2}-6\sqrt{2}+10\sqrt{2}=5+\sqrt{2}\).
\(2\sqrt{6}\cdot3\sqrt{24}-\sqrt{144}=6\sqrt{144}-12\).
\(=6\cdot12-12=72-12=60\).
\(4\sqrt{8}-3\sqrt{18}+2\sqrt{98}=4\cdot2\sqrt{2}-3\cdot3\sqrt{2}+2\cdot7\sqrt{2}\).
\(=8\sqrt{2}-9\sqrt{2}+14\sqrt{2}=13\sqrt{2}\).
Ответ: 1) \(7\sqrt{3}\); 2) \(5+\sqrt{2}\); 3) \(60\); 4) \(13\sqrt{2}\).
