Ответ:
\(\sqrt{20}-2\sqrt{180}+\sqrt{20}=2\sqrt5-12\sqrt5+2\sqrt5=-8\sqrt5\).
\(\sqrt{50}-3\sqrt{200}+\sqrt{125}=5\sqrt2-30\sqrt2+5\sqrt5=5\sqrt5-25\sqrt2\).
\(4\sqrt2+\sqrt{50}-\sqrt{18}=4\sqrt2+5\sqrt2-3\sqrt2=6\sqrt2\).
\(\frac12\sqrt{12}-2\sqrt{27}+\sqrt{75}=\sqrt3-6\sqrt3+5\sqrt3=0\).
\(\frac13\sqrt{18}+3\sqrt8-\sqrt{98}=\sqrt2+6\sqrt2-7\sqrt2=0\).
\(2\sqrt5(\sqrt{20}-3\sqrt5)=2\sqrt5(2\sqrt5-3\sqrt5)=-10\).
\((\sqrt{11}+2\sqrt5)(\sqrt{11}-2\sqrt5)=11-20=-9\).
Ответ: а) \(-8\sqrt5\); б) \(5\sqrt5-25\sqrt2\); в) \(6\sqrt2\); г) 0; д) 0; е) −10; ж) −9.
