2. Вычислите: 1) √0,49 − √0,04; √36 · √9; √25 : √400. 2) √1369 − √1681; 5/√4225 − √(25/169); 1/√361 − √6,25.

1)

\(\sqrt{0.49}-\sqrt{0.04}=0.7-0.2=0.5\).

\(\sqrt{36}\cdot\sqrt{9}=6\cdot3=18\).

\(\sqrt{25}:\sqrt{400}=5:20=0.25\).

2)

\(\sqrt{1369}-\sqrt{1681}=37-41=-4\).

\(\frac{5}{\sqrt{4225}}-\sqrt{\frac{25}{169}}=\frac{5}{65}-\frac{5}{13}=\frac{1}{13}-\frac{5}{13}=-\frac{4}{13}\).

\(\frac{1}{\sqrt{361}}-\sqrt{6.25}=\frac{1}{19}-2.5=\frac{1}{19}-\frac{5}{2}=-\frac{93}{38}\).

Ответ: 1) 0,5; 18; 0,25. 2) −4; \(-\frac{4}{13}\); \(-\frac{93}{38}\).