2. Вычислите: 1) (3² · 4³ · 12²)/(9² · 6³); 2) (5² · 6⁴ · 12²)/(15² · 9³); 3) (12² · 4⁴ · 6²)/(8² · 18³); 4) ((8³)³ · 9⁷ · 2²)/(81⁵ · 2³).

1. \(\frac{3^2\cdot4^3\cdot12^2}{9^2\cdot6^3}=\frac{9\cdot64\cdot144}{81\cdot216}=\frac{16}{3}\).
2. \(\frac{5^2\cdot6^4\cdot12^2}{15^2\cdot9^3}=\frac{25\cdot1296\cdot144}{225\cdot729}=\frac{64}{9}\).
3. \(\frac{12^2\cdot4^4\cdot6^2}{8^2\cdot18^3}=\frac{144\cdot256\cdot36}{64\cdot5832}=\frac{16}{9}\).
4. \(\frac{(8^3)^3\cdot9^7\cdot2^2}{81^5\cdot2^3}=\frac{2^{27}\cdot3^{14}\cdot2^2}{3^{20}\cdot2^3}=\frac{2^{26}}{3^6}=\frac{67108864}{729}\).

Ответ: 1) \(\frac{16}{3}\); 2) \(\frac{64}{9}\); 3) \(\frac{16}{9}\); 4) \(\frac{67108864}{729}\).