2) Вычислите: √1225 − √2116; 1/√289 + √2,25; 3/√1089 − √(49/121).

1. \(\sqrt{1225}-\sqrt{2116}=35-46=-11\).
2. \(\frac{1}{\sqrt{289}}+\sqrt{2.25}=\frac{1}{17}+1.5=\frac{1}{17}+\frac{3}{2}=\frac{53}{34}\).
3. \(\frac{3}{\sqrt{1089}}-\sqrt{\frac{49}{121}}=\frac{3}{33}-\frac{7}{11}=\frac{1}{11}-\frac{7}{11}=-\frac{6}{11}\).

Ответ: −11; \(\frac{53}{34}\); \(-\frac{6}{11}\).