2. Вычислите: 3) √16 − √25; √25 · √4; √49 : √400. 4) √1225 − √2116; 1/√289 + √2,25; 3/√1089 − √(49/121).

3)

\(\sqrt{16}-\sqrt{25}=4-5=-1.\)

\(\sqrt{25}\cdot\sqrt{4}=5\cdot2=10.\)

\(\sqrt{49}:\sqrt{400}=7:20=\frac{7}{20}.\)

4)

\(\sqrt{1225}-\sqrt{2116}=35-46=-11.\)

\(\frac{1}{\sqrt{289}}+\sqrt{2.25}=\frac{1}{17}+1.5=\frac{1}{17}+\frac{3}{2}=\frac{53}{34}.\)

\(\frac{3}{\sqrt{1089}}-\sqrt{\frac{49}{121}}=\frac{3}{33}-\frac{7}{11}=\frac{1}{11}-\frac{7}{11}=-\frac{6}{11}.\)

Ответ: 3) −1; 10; 7/20. 4) −11; 53/34; −6/11.