Ответ:
а) НОК(10, 15) = 30.
\(3\frac{7}{10}-1\frac{4}{15}=2+\left(\frac{21}{30}-\frac{8}{30}\right)=2\frac{13}{30}\).
б) НОК(12, 15) = 60.
\(5\frac{1}{12}-2\frac{7}{15}=5\frac{5}{60}-2\frac{28}{60}=4\frac{65}{60}-2\frac{28}{60}=2\frac{37}{60}\).
в) НОК(35, 20) = 140.
\(6\frac{9}{35}-5\frac{13}{20}=6\frac{36}{140}-5\frac{91}{140}=1-\frac{55}{140}=\frac{17}{28}\).
г) НОК(30, 42) = 210.
\(4\frac{7}{30}-3\frac{5}{42}=4\frac{49}{210}-3\frac{25}{210}=1+\frac{24}{210}=1\frac{4}{35}\).
Ответ: а) \(2\frac{13}{30}\); б) \(2\frac{37}{60}\); в) \(\frac{17}{28}\); г) \(1\frac{4}{35}\).
