№ 2. Вычислите: \(\sqrt{27}\cdot\sqrt{120}\); \(\frac{\sqrt{162}}{\sqrt2}\).

1. \(\sqrt{27}\cdot\sqrt{120}=\sqrt{27\cdot120}=\sqrt{3240}=\sqrt{324\cdot10}=18\sqrt{10}\).

2. \(\frac{\sqrt{162}}{\sqrt2}=\sqrt{\frac{162}{2}}=\sqrt{81}=9\).

Ответ: \(18\sqrt{10}\); 9.