Ответ:

  1. \[\frac{21}{40}+\frac{17}{40}-\frac{15}{40}=\frac{21+17-15}{40}=\frac{23}{40}.\]
  2. \[\frac{8}{11}-\left(\frac{1}{3}+\frac{1}{4}\right)=\frac{8}{11}-\frac{7}{12}=\frac{96}{132}-\frac{77}{132}=\frac{19}{132}.\]
  3. \[1-\frac{13}{20}=\frac{20}{20}-\frac{13}{20}=\frac{7}{20}.\]
  4. \[\left(10-5\frac{3}{10}\right)\cdot\frac{10}{17}=\frac{47}{10}\cdot\frac{10}{17}=\frac{47}{17}=2\frac{13}{17}.\]

Ответ: а) \(\frac{23}{40}\); б) \(\frac{19}{132}\); в) \(\frac{7}{20}\); г) \(2\frac{13}{17}\).