2. Выполнить действия с обыкновенными дробями:

2. Выполнение действий с обыкновенными дробями:

1. \( \frac{3}{4} + 2 = \frac{3}{4} + \frac{8}{4} = \frac{11}{4} \)
2. \( \frac{8}{15} : 4 = \frac{8}{15} \cdot \frac{1}{4} = \frac{2}{15} \)
3. \( 3 : \frac{3}{2} = 3 \cdot \frac{2}{3} = 2 \)
4. \( \frac{7}{12} - 1 = \frac{7}{12} - \frac{12}{12} = -\frac{5}{12} \)
5. \( \frac{1}{3} - \frac{1}{2} = \frac{2}{6} - \frac{3}{6} = -\frac{1}{6} \)
6. \( \frac{2}{4} + 3 \frac{5}{7} = \frac{1}{2} + \frac{26}{7} = \frac{7}{14} + \frac{52}{14} = \frac{59}{14} \)
7. \( -4 \frac{2}{7} + 7 \frac{1}{2} = -\frac{30}{7} + \frac{15}{2} = -\frac{60}{14} + \frac{105}{14} = \frac{45}{14} \)
8. \( -5 \frac{1}{2} + 4 \frac{1}{3} = -\frac{11}{2} + \frac{13}{3} = -\frac{33}{6} + \frac{26}{6} = -\frac{7}{6} \)
9. \( -3 \frac{1}{2} \cdot 2 \frac{2}{5} = -\frac{7}{2} \cdot \frac{12}{5} = -\frac{84}{10} = -\frac{42}{5} \)
10. \( -4 \frac{5}{7} \cdot \left( -2 \frac{6}{11} \right) = -\frac{33}{7} \cdot \left( -\frac{28}{11} \right) = \frac{33 \cdot 28}{7 \cdot 11} = \frac{3 \cdot 4}{1} = 12 \)
11. \( \frac{7}{12} : \left( -\frac{1}{4} \right) = \frac{7}{12} \cdot (-4) = -\frac{28}{12} = -\frac{7}{3} \)
12. \( \frac{7}{9} \cdot \frac{18}{35} = \frac{7 \cdot 18}{9 \cdot 35} = \frac{1 \cdot 2}{1 \cdot 5} = \frac{2}{5} \)
13. \( 2 \frac{1}{6} - 7 \frac{5}{6} = \frac{13}{6} - \frac{47}{6} = -\frac{34}{6} = -\frac{17}{3} \)
14. \( -2 \frac{2}{3} - 3 \frac{5}{9} = -\frac{8}{3} - \frac{32}{9} = -\frac{24}{9} - \frac{32}{9} = -\frac{56}{9} \)
15. \( 4 \frac{1}{3} : 2 \frac{5}{6} = \frac{13}{3} : \frac{17}{6} = \frac{13}{3} \cdot \frac{6}{17} = \frac{13 \cdot 2}{17} = \frac{26}{17} \)

Ответ: \(\frac{11}{4}, \frac{2}{15}, 2, -\frac{5}{12}, -\frac{1}{6}, \frac{59}{14}, \frac{45}{14}, -\frac{7}{6}, -\frac{42}{5}, 12, -\frac{7}{3}, \frac{2}{5}, -\frac{17}{3}, -\frac{56}{9}, \frac{26}{17}\)